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6x^2+5x=56
We move all terms to the left:
6x^2+5x-(56)=0
a = 6; b = 5; c = -56;
Δ = b2-4ac
Δ = 52-4·6·(-56)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-37}{2*6}=\frac{-42}{12} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+37}{2*6}=\frac{32}{12} =2+2/3 $
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